Question

The molarity of 98% H2SO4 (d=1.8g/ml) by weight is?

Answer 1

% of the sulphuric Acid in the solution = 98 %

This means that 98 g of the sulphuric acid is present in the 100 g of the solution.

Molar Mass = 98 g/mole.

∵ No. of moles = Mass/Molar mass

∴ No. of moles = 98/98

= 1 moles.

Also, Density of the solution = 1.8 g/cm³.

∵ Density = Mass/Volume.

∴ Volume = 100/1.8

= 55.56 cm³

= 0.0556 L.

Now, Using the Formula,

Molarity = No. of moles of solute/Volume of the solutions in liter.

= 1/0.0556

= 17.98 M.

Hence, the molarity of the solution is 17.98 M.

Hope it helps.

Answer 2

Explanation:

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