The pair of linear equations (3k+1)x+3y-5=0 and 2x-3y+5=0 have infinite solutions.Then find the value of k.
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if they have infinite solution then
(3k+1)/2=3/-3=-5/5
or 3k+1/2=-1
3k+1=-2
3k=-3
k=-1
(3k+1)/2=3/-3=-5/5
or 3k+1/2=-1
3k+1=-2
3k=-3
k=-1
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