Question

a convex lens froms a real and innert image needle at a distance of 50 cm from it where is the needle placed in front of convex lens if image is equal to the size of the object also find power of the lens?
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Answer 1

Answer:

here is your answer...

the needle should be placed at 2F to obtain a equal and inverted image.

f =- 50 cm= -1/2 m

P= 1/f

hence power= 2 diopter

hope it helps.

Answer 2

Hey Happy Soul ❤

Your Answer :

The position of image should be at 2F, since the image is real and same size.

It is given that the image of the needle is formed at a distance of 50 cm from the convex lens.

Therefore, the needle is placed in front of the lens at a distance of 50 cm.

Focal length :

Object distance (u) = - 50 cm

Image distance, (v) = 50 cm

Focal length = f

According to the lens formula,

1/v - 1/u = 1/f

1/f = 1/50 - 1/(-50)

1/f = 1/50 + 1/50

1/f = 1/25

f = 25 cm = 0.25 m

Power of lens :

p = 1 / f ( in meter)

p = 1/0.25 = +4 D

Hope this will helps you ☺

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