Question

A convex lens of focal length 0.10 misused to form a magnified image of an object of height 5 m placed at a distance of 0.08 m from the lens. Calculate the position, nature and size of the image.

Answer 1

Answer:

Image position at 49cm, height is 2.5cm and nature is virtual and erect.

Explanation:

Since, we know that the focal length f is given as 0.10m = 10cm.

Object distance is u = -0.08 m = -8cm and the height of the object is 0.5cm.

So, on applying lens formulae we will get that 1/v - 1/u = 1/f .

So, on substituting the values we will get 1/v = 1/10 + 1/(-8) so on solving we will get v = -40cm.

Thus, the position of the image is 40cm which will be present on the same side of object.

Magnification is h1/0.5 or (-30)/(-8) which on solving we will get the value of magnification to be +5.