A convex lens of focal length 10 cm is placed at a distance of 12 cm from a wall . How far from the lens should an object be placed so as to form its real image on the wall?
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by mirror formula,
1/u - 1/y = 1/f
sign convention is distance from the centre of the lens to be positive in one direction and negative in the other -
=>> 1/12 - 1/u = 1/10
=>> 1/u - 1/12 - 1/10 = -1/60
=>> The object to be place on side opposite to that of the wall at a distance of 60 cm, from the lens.
I hope it's help U :-)
1/u - 1/y = 1/f
sign convention is distance from the centre of the lens to be positive in one direction and negative in the other -
=>> 1/12 - 1/u = 1/10
=>> 1/u - 1/12 - 1/10 = -1/60
=>> The object to be place on side opposite to that of the wall at a distance of 60 cm, from the lens.
I hope it's help U :-)
AnshumanSatapathy:
why did you use the mirror formula,I guess lens equation should be used
Answered by
2
v=12cm,f=10cm 1/v+1/u = 1/f , u= f×v/v-f = 10×12/12-10= 120/2= 60cm
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