A convex lens of focal length 10cm is placed in closed contact with a concave lens of focal length 5cm. The power of combination is
20 D
10 D
-20 D
-10 D
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Answer:
Option d) -10D is correct
Explanation:
Given :
Focal length of convex lens f₁ = + 10 cm = + 0.1 m
Focal length of concave lens f₂ = - 5 cm = - 0.05 m
Power of convex lens P₁ = 1/f₁ = + 1/0.1 = + 10 D
Power of concave lens P₂ = 1/f₂ = - 1/0.05 = - 20 D
Power of combination P = P₁ + P₂
= 10 - 20
= - 10 D
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