If n(A) = 15 , n(B) = 21 and n(AUB) = 29 then n(A intersection B) = ? solve it please
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Step-by-step explanation:
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Answer:
n(A intersection B) = 7
Step-by-step explanation:
Given:
- n(A) = 15
- n(B) = 21
- n(AUB) = 29
To find:
n(A∩B) = ?
Solution:
Here we use a particular formula for n(AUB) in Set Theory i.e.
n(AUB) = n(A) + n(B) - n(A∩B)
→ 29 = 15 + 21 - n(A∩B)
→ 29 = 36 - n(A∩B)
→ n(A∩B) = 36 - 29
→ n(A∩B) = 7
∴ n(A∩B) = 7
KNOW MORE:
De Morgans' laws:
- Law of union: (A U B)' = A' ∩ B'
- Law of intersection: (A ∩ B)' = A' U B'
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