A convex lens of focal length 20cm produces 3 times
Answers
Answered by
3
i) For real image
Given , M = -3
m = v/u
-3 = v/u
v = -3u ...................... (i)
by lens formula
1/f = 1/v -1/u
1/20 = -1/3u -1/u
1/20 = -4/3u
u= -4 x 20/3 = - 80/3 cm
for virtual image
m= +3
m= v/u
3= v/u
v=3u
by lens formula
1/f = 1/v - 1/u
1/20 = 1/3u - 1/u
1/20= -2/3u
u= -2 x 20/3 = -40/3 cm.
therefore the two positions of the object are:
-80/3 cm and -40/3 cm
Given , M = -3
m = v/u
-3 = v/u
v = -3u ...................... (i)
by lens formula
1/f = 1/v -1/u
1/20 = -1/3u -1/u
1/20 = -4/3u
u= -4 x 20/3 = - 80/3 cm
for virtual image
m= +3
m= v/u
3= v/u
v=3u
by lens formula
1/f = 1/v - 1/u
1/20 = 1/3u - 1/u
1/20= -2/3u
u= -2 x 20/3 = -40/3 cm.
therefore the two positions of the object are:
-80/3 cm and -40/3 cm
Answered by
0
For real image
Given , M = -3
m = v/u
-3 = v/u
v = -3u .. (i)
by lens formula
1/f = 1/v -1/u
1/20 = -1/3u -1/u
1/20 = -4/3u
u= -4 x 20/3 = - 80/3 cm
for virtual image
m= +3
m= v/u
3= v/u
v=3u
by lens formula
1/f = 1/v - 1/u
1/20 = 1/3u - 1/u
1/20= -2/3u
u= -2 x 20/3 = -40/3 cm.
therefore the two positions of the object are:
-80/3 cm and -40/3 cm
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