A convex lens placed at a distance of 16 cm from
an object produces an image of magnification
m(ml> 1). If the object is moved towards the lens
by 8 cm, then again an image of magnification m is
obtained. The numerical value of the focal length of
the lens is
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Explanation:
Given A convex lens placed at a distance of 16 cm from an object produces an image of magnification m(ml> 1). If the object is moved towards the lens by 8 cm, then again an image of magnification m is obtained. The numerical value of the focal length of the lens is
We know that 1/v – 1/u = 1/f
So u/v – 1 = 1/f
Now m = v/u = f / f + u
Given u1 = - 16, u2 = - 8
Also m1 = m, m2 = - m
Now f/f – 16 = - f / f – 8
So f^2 – 8 f = - f^2 + 16 f
2f^2 – 24 f = 0
So f^2 – 12 f = 0
Or f = 12 cm
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