Question

A convex mirror has a radius of curvature of 60 cm. If a 2.2 m tall object is placed 4 m in front of the mirror. Where is the image located and how tall is it

Answer 1

Answer:

Given :- Radius of curvature 60cm, Size of Object is (2.2)100= 220cm and Distance of Object is 4×100= -400cm.

Sol:-

F = R/2

F = 400/2

F = 200cm

1/v + 1/u = 1/f

1/v = 1/f - 1/u

1/v = 1/200 - 1/(-400)

1/v = 1/200 + 1/400

1/v = ( 2/400 + 1/400)

1/v = 3/400

1/v = 400/3

1/v = 133.3cm

m = h'/h = -v/u

h'/220= -(133.3)/(-400)

h'= 39.9cm

Position of image is 133.3cm

Nature of image is virtual and erect

Size of image is 40cm approx.

Hope this will helpful