A convex mirror is used in a bus has radius of curvature 3.5m.If the driver of the bus locates a car at 10.0m behind the bus, find the position, nature and size of the image of the car.
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Given: radius of Curvature - R = 3.5m
Object distance - u = -10m
To Find:
image distance - v = ?
size and nature of the image
Solution:
Formula used:
- focal length - f = R/2
- 1/f = 1/v + 1/u
- magnification - m = - height of image/height of object = -v/u
Applying the above formulas to calculate the focal length "f" of the mirror and image distance"v".
f = R/2 = 3.5/2
f = 1.75
1/f = 1/v + 1/u
1/1.75 = 1/v - 1/10
1/v = 1/1.75 + 1/10
1/v = 0.57 + 0.1
1/v = 0.67
1/v = 67/100
v = 100/47
v = 1.5m
Applying the formula of magnification to find the nature of the image.
m = - v/u
m = - 1.5/-10
m = 0.15
Hence, the image is erect, virtual as the magnification is positive, and diminished as m < 1.
And image position is 1.5m.
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