A convex mirror on a bus (as a revers view mirror)has radius of curvature 3.00m it the distance of bus 5m then find the position and nature and size of image
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Radius of curvature of the convex mirror R = 3 m
Focal length of the convex mirror f = R/2 = 1.5 m (positive for convex mirror)
Object (bus) distance u = − 5 m
Image distance v = ?
Mirror formula is: 1/f = 1/v + 1/u
1/1.5 = 1/v + 1/(−5)
1/v = 1/1.5 + 1/5
= (5 + 1.5)/(5 x 1.5) = 6.5/7.5
v = 7.5/6.5
= 1.15 m
Position of the image is at 1.15 m behind the mirror.
Focal length of the convex mirror f = R/2 = 1.5 m (positive for convex mirror)
Object (bus) distance u = − 5 m
Image distance v = ?
Mirror formula is: 1/f = 1/v + 1/u
1/1.5 = 1/v + 1/(−5)
1/v = 1/1.5 + 1/5
= (5 + 1.5)/(5 x 1.5) = 6.5/7.5
v = 7.5/6.5
= 1.15 m
Position of the image is at 1.15 m behind the mirror.
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f = +1.5m
u = -5m
v = +1.15m
position of image= between c and f.
nature= real, inverted, and can be obtained on screen.image is smaller than object.
u = -5m
v = +1.15m
position of image= between c and f.
nature= real, inverted, and can be obtained on screen.image is smaller than object.
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