A convex mirror used for rear-view on an automobile has a radius of curvature of 4.00 m. If a bus is located at 5.00 m from this mirror, the size of the image will be: (Ask)
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Given:-
- Radius of Curvature ,R = 4m
- Object Distance ,u = 5m
To Find:-
- Image distance ,v
- Height of image ,hi
Solution:-
As we know that the relationship between Radius of Curvature and Focal length .
• f = R/2
Substitute the value we get
→ f = 4/2 = 2 m
Now, Calculating the image distance using mirror formula.
• 1/v + 1/u = 1/f
where,
v is the Image Position
u is the object distance
f is the focal length
Substitute the value we get
→ 1/v = 1/f - 1/u
→ 1/v = 1/2 -1/(-5)
→ 1/v = 1/2 + 1/5
→ 1/v = 5+2/10
→ 1/v = 7/10
→ v = 10/7
→ v = 1.42 m
Therefore,the image distance is 1.42 m at the back of mirror.
Now,
magnification ,m = hi/ho = -v/u
substitute the value we get
→ hi/ho = -1.42/-5
→ hi/ho = 1.42/5
→ hi/ho = 0.28
→ hi = 0.28 ho
The image is virtual , erect and smaller in size and height of image is 0.28 m .
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