Question

An object of 2500g is lifted by a person through a height of 2.5 m. Work done by him on the object is: *

1. 62500 J
2. 62.5 J
3. 6.25 J
4. 6250 J

Answer 1

Answer:

Good morning

Explanation:

Have a nice day

Answer 2

Answer :

• Option (2) 62.5 J

S O L U T I O N :

Given,

• Mass (m) = 2500 g ⟹ 2500/1000 ⟹ 2.5 kg.

• Height (h) = 2.5 m.

• Acceleration due to gravity (g) = 10 m/s².

To Find,

• Work done by him on the object.

Explanation,

According to the work - Energy theorem,

⟹ Work done = Increasing in Potential energy

⟹ W = P.E

.°. Work done = mgh

[ Put the values ]

⟹ W = 2.5 × 10 × 2.5

⟹ W = 25 × 2.5

⟹ W = 62.5 J

Therefore,

The work done by him on the object is 62.5 joule.

For information,

• K.E = ¹/2 × mv²
• M.E = P.E + K.E