a convex mirror used in a bus has radius of curvature 3.5 metre is the driver of the bus locates a car at 10 metre behind the bus find the position nature and size of the image of the car.
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R=3.5 , f=R/2= 1.75m
u= -10cm, v=?
1/f =1/v + 1/u
1/1.75 = 1/v - 1/10
v= 1.5 m
magnification (m)= -v/u =0.15
image is real, erect and diminished
Anonymous:
nyc✔✔✔✔
Answered by
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ANSWER:-----------------
R= 3.5
U= 10.0
f= R/2 =3.5/2
3.5°10/2°10
35/20
7/4
1.75
1/f= 1/v +1/u 1/v = 1/f- 1/u 1/v= 1/1.75-1/-10
= 1/7/4-1/-10 =4/7- 1/-10
= -40-7\ 70 = 47/70
v = 70\47
v = 1.5
m= -v\u
m = -1.5\[-10]
= 0.15 An
hope it helps:--
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