A convex mirror with a radius of 3cm is used as a rare view mirror for a vehicle. If a bus is located at 5m from the mirror , find the position , nature and size of the image
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Object distance (u)= -5m (always negative)
radius of curvature C = 3m
focal length = 3/2 = 1.5m.
with formula we know that ,
1/v +1/u = 1/f
1/v = 1/1.5 - 1/-5
1/v = -5 - 1.5 /-7.5
1/v = -6.5/-7.5
v = 1.15m
we must find magnification,
m= -v/u
= -1.15/-5
=0.23
the image is formed on the opposite side of the object.so it will be virtual and erect.
and 0.23 is very small where the object is placed beyond C.
so the image is virtual ,diminished and erect.
hope it helps!!!
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ANSWER:-----------------
R= 3.5
U= 10.0
f= R/2 =3.5/2
3.5°10/2°10
35/20
7/4
1.75
1/f= 1/v +1/u 1/v = 1/f- 1/u 1/v= 1/1.75-1/-10
= 1/7/4-1/-10 =4/7- 1/-10
= -40-7\ 70 = 47/70
v = 70\47
v = 1.5
m= -v\u
m = -1.5\[-10]
= 0.15 An
hope it helps:--
T!—!ANKS!!!
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