A convex mirror with a radius of curvature of 3m is used as rear view mirror for a vehicle. if a is located at 5m from mirror find the position
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8
Radius of curvature of the convex mirror R = 3 m
Focal length of the convex mirror f = R/2 = 1.5 m (positive for convex mirror)
Object (bus) distance u = − 5 m
Image distance v = ?
Mirror formula is: 1/f = 1/v + 1/u
1/1.5 = 1/v + 1/(−5)
1/v = 1/1.5 + 1/5
= (5 + 1.5)/(5 x 1.5) = 6.5/7.5
v = 7.5/6.5
= 1.15 m
Position of the image is at 1.15 m behind the mirror.
Focal length of the convex mirror f = R/2 = 1.5 m (positive for convex mirror)
Object (bus) distance u = − 5 m
Image distance v = ?
Mirror formula is: 1/f = 1/v + 1/u
1/1.5 = 1/v + 1/(−5)
1/v = 1/1.5 + 1/5
= (5 + 1.5)/(5 x 1.5) = 6.5/7.5
v = 7.5/6.5
= 1.15 m
Position of the image is at 1.15 m behind the mirror.
Answered by
5
Given,
Radius of curvature of convex mirror is =3m.
Object distance (u) = -5m(object distance will be negative according to sign convention)
Then find the position,size and nature of image.
We know that,
Focal length is half of radius of curvature.
F = R/2
F = 3/2
F = 1.5m
The mirror formula: 1/f = 1/u+1/v
Where,
f = focal length
u = object distance
v = image distance
Now,substitute the know values in the formula.
==> 1/1.5 = 1/-5+1/v
==> 1/v = 1/1.5+1/5
==> 1/v = 5+1.5/7.5
==> 1/v = 6.5/7.5
==> v = 7.5/6.5
==> v = 1.15m
Therefore the image distance is 1.15m.
Magnification: hi/ho = -v/u
= -1.15/-5
=0.23
Therefore image is virtual seen at the back in the mirror.
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