Question

a convex polygon has 44 diagonals how many sides does it have​

Answer 1

Step-by-step explanation:

d=n(n-3)÷2

diagonals (d)=44

44=n(n-3)÷2

88=n^2-3n

n^2-3n-88=0

n^2-11n+8n-88=0

n(n-11)+8(n-11)=0

n-11=0 and n+8=0

n=11

n means no of sides.

but n+8=0 means n value -8 its impossible. so polygon sides total 11