Question

A cooking cylinder can with stand a pressure of 24 atm. At 27 °C the pressure of the containing gas 12 atm, then the minimum temperature above which cylinder will explode is
​

Answer 1

Answer:

600K

Explanation:

we know that initial pressure(P1) is 12 atm and the final pressure(P2) is 24 atm. the volume of the gas inside the cylinder is assumed to be constant, as a cylinder is not changing in size.

P1/T1=P2/T2

solving for T2 we get:-

T2=(P2×T1)/P1

=(24atm×300K)/12atm

=600K

therefore the minimum temperature above which cylinder will explode is 300K or 327°C

(rounded to the nearest degree)