Question

. A cooler of 1500 W, 200 volt and a fan of 500 W, 200 volt are to be used from a household supply. The rating of fuse to be used is

Answer 1

Answer:

total power used ,P=P1+P2= 1500 + 500 =2000W current drawn from the supply ,I=p/v = 2000/200 =10 Ampere is correct Answer