Question

A coolie carries a 20 kg load on his head and take it to a overhead Bridge 10 M high. What is the work done by the coolie? Take g=10 ms-²

Answer 1

Explanation:

Mass = mg

mass=20000g acceleration = gravity =10

f = m×a

f=20000×10=2×10^5N

w=f×ds

w=2×10^5×10=2×10^6 Nm^2

Answer 2

Answer:

The work done by the coolie $0J$ .

Explanation:

Given :  mass = $20kg$

              g = $10 m/s^{2}$

             displacement (s) = $10m$

Since the angle between the load and the direction of the move is $90^{0}$ .

Work done = Force x Displacement

                   = mg x s x cos θ

                   =  $20\times 10\times 10cos90^{0}$

                   = $0J$

Hence, the work done by the coolie $0J$ .

#SPJ3