A coolie lifts a box of 25kg from the ground to a height of 5.0 metres. the work done by the coolie on the box is (g=10m/s)
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Answer:
Work done= m×g×h
=25×10×5
=1250 Joules
Explanation:
Answered by
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Answer:
Explanation:
GIVEN: m=25kg
h=5.0 metres
to find - work done
solution - work done = Fs cosФ
Since the coolie holds the box perpendicular and thus force applied & distance is perpendicular work done will be 0
As cos 90 = 0
work done = 0 joule
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