Question

A coolie lifts a box of 25kg from the ground to a height of 5.0 metres. the work done by the coolie on the box is (g=10m/s)

Answer 1

Answer:

Work done= m×g×h

=25×10×5

=1250 Joules

Explanation:

Answer 2

Answer:

Explanation:

GIVEN: m=25kg

h=5.0 metres

to find - work done

solution - work done = Fs cosФ

Since the coolie holds the box perpendicular and thus force applied & distance is perpendicular work done will be 0

 As cos 90 = 0

work done = 0 joule