A copp
er wire of length 2m and areas
of cross section 1.7*10-6 meter 2 has a
resistence of 2*10*2ohms calculate the resistivity of copper?
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Hola User ___________
Here is Your Answer....!!!
_____________________
Actually welcome to the concept of the current electricity .....
So Basiclly we know that ....
R = p × l/A
So as given here .... R = 2 × 10^-2 ohm
l = 2m and A = 1.7 × 10^-6 m^2 ....
So we get that .... p (rho) = R A ÷ l
p = 2 × 10^-2 × 1.7 × 10 ^-6 ÷ 2
p = 1.7 × 10^-8
thus the resistivity is given as 1.7 x 10^-8 .... ohm - metre
________________________€
Hope it helps u.....☺
Here is Your Answer....!!!
_____________________
Actually welcome to the concept of the current electricity .....
So Basiclly we know that ....
R = p × l/A
So as given here .... R = 2 × 10^-2 ohm
l = 2m and A = 1.7 × 10^-6 m^2 ....
So we get that .... p (rho) = R A ÷ l
p = 2 × 10^-2 × 1.7 × 10 ^-6 ÷ 2
p = 1.7 × 10^-8
thus the resistivity is given as 1.7 x 10^-8 .... ohm - metre
________________________€
Hope it helps u.....☺
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