Question

A copper
0.5 mm
wire has a diameter
and desistivity 1.6 X 10~8
How much will be
of another copper
lehsth but halls
the resistance
wire of Saone
the dianDeter.

Answer 1

Answer:

The new resistance is 2.5 Ω

Step-by-step explanation:

Ans: Area of cross-section of the wire, A =π (d/2) 2

Diameter= 0.5 mm = 0.0005 m

Resistance, R = 10 Ω

We know that

∴ length of the wire = 122.72m

If the diameter of the wire is doubled, new diameter=2×0.5=1mm=0.001m

Let new resistance be Rʹ

∴ the new resistance is 2.5 Ω

Answer 2

Step-by-step explanation:

Ris proportional to l and inversely to Area. R=resistivity constant x length/area. Then it is simple. find it out. I think it will be 4 times the resistance of first copper wire. check it oit.