A copper block of mass 2.5 kg is heated in a furnace to a temperature of 500 °C and then placed on a large ice block. What is the maximum amount of ice that can melt? (Specific heat of copper = 0.39 J g –1 K –1 ; heat of fusion of water = 335 J g –1 ).
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we know
heat loss =heat gain
maximum heat loss by copper block =mSdT
=2500g x 0.39jg-1k-1 x (500-0) k
=487,500 j
now
487500 j=M L
where M is the mass of ice melted and L is latent heat of fusion .
487500 j =M x 335jg-1
M=1455.22 g =1.45522 kg
heat loss =heat gain
maximum heat loss by copper block =mSdT
=2500g x 0.39jg-1k-1 x (500-0) k
=487,500 j
now
487500 j=M L
where M is the mass of ice melted and L is latent heat of fusion .
487500 j =M x 335jg-1
M=1455.22 g =1.45522 kg
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