Question

A copper block of mass kg is heated till it's t is increased by 20 degree celcius. Fing the heat supplied to the block. Specific heat

Answer 1

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Mass of the copper block, m = 2.5 kg = 2500 g
Rise in the temperature of the copper block, Δθ = 500°C
Specific heat of copper, C = 0.39 J g–1 °C–1
Heat of fusion of water, L = 335 J g–1
The maximum heat the copper block can lose,Q = mCΔθ
= 2500 × 0.39 × 500
= 487500 J
Let m1 g be the amount of ice that melts when the copper block is placed on the ice block.
The heat gained by the melted ice, Q = m1L
∴ m1 = Q / L  =  487500 / 335  =  1455.22 g
Hence, the maximum amount of ice that can melt is 1.45 kg.


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