Question

A copper coin has a mass of 63.0 g. Calculate the nuclear energy that
would be required to separate all the neutrons and protons from each
other. The coin is entirely made of 2% Cu atoms.
Mass of 2 Cu atom = 62.92960 u
Mass of proton = 1.00727 u
Mass of neutron = 1.00866 u
Avogadro's number = 6.022 x 1023.​

Answer 1

Answer:

Energy required to separate neutrons and protons of all copper atom is given as

$U = 1.03 \times 10^{12} J$

Explanation:

As we know that energy released due to dissociation of 1 atom is given as

$Q = \Delta m c^2$

so we have

$Q = (29 m_p + 34 m_n - M) c^2$

$Q = (29(1.00727) + 34(1.00866) - 62.92960)(931)$

$Q = 535.9 MeV$

Now total atoms of copper in the coin

$N =0.02 \frac{m}{M}(6.02 \times 10^{23})$

$N = 1.2 \times 10^{22}$

Now total energy required is given as

$U = 1.2 \times 10^{22} (535.9)(1.6 \times 10^{-13})$

$U = 1.03 \times 10^{12} J$

#Learn

Topic : Binding energy

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