A copper rod diameter 1cm snd length 8cm is drawn in to a wire of length 18m uniform thickness.Find the thickness of wire.??
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Diameter = 1cm
Length = 8cm (h)
Then, radius (r) = 0.5 cm (diameter/2)
Therefore volume of cylindrical copper rod = πr²h = π(0.5)²(8) = 2π cm²
length of wire(H) = 18 m = 1800 cm
Let thickness of wire = 2R
then, volume of cylindrical wire = πR²H = 18πR²
Since the rod is drawn into the wire:
now, volume of wire = volume of rod
then, 1800πR² = 2π
900R² = 1 (dividing by 2π on both sides)
R² = 1/900
R = 1/30 cm
Therefore, Diameter(thickness) of wire = 2R = 2/30 cm = 1/15 cm = 0.67 mm
ANSWER = 1/15 cm = 0.67 mm
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