Question

A copper rod of diameter 1 cm and length of 8 cm is drawn into a wire of length 18 metre of uniform thickness find the thickness of wire??


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Answer 1

The volume of the rod = π×(21)2×8=2π cm3

The length of the new wire of the same volume = 18 m = 1800 cm

If r is the radius ( in cm ) of cross-section of the wire, its voume = π×r2×1800 cm3

Therefore,

π×r2×1800=2π

2=9001

r=301

So, the diameter of the cross section, i.e., the thickness of the wire is 151 cm, i.e., 0.67 mm

Answer 2

Answer:

hii mate here is your answer

Step-by-step explanation:

Diameter of the copper wire = 1 cm

So, radius of the copper wire = 1/2 cm = 0.5 cm

Length of the copper rod = 8 cm We know that,

Volume of the cylinder = π r2h = π × 0.52 × 8 ……. (i)

Length of the wire = 18 m = 1800 cm Volume of the wire = π r2h = π r2 × 1800 ….. (ii)

On equating both the equations, we have π × 0.52 × 8 = π r2 × 1800 r2 = 2 /1800 = 1/900 r = 1/30 cm

Therefore, the diameter of the wire is 1/15 cm i.e. 0.67 mm which is the thickness of the wire.

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