Question

a copper vessel of mass 300 g contains 1 litre of water. Calculate the amount of heat needed to raise the temperature from 15 degree to 85 degree celcius​

Answer 1

Answer:

Explanation:

m  

w

​  

c  

w

​  

Δt+m  

c

​  

c  

c

​  

Δt=m  

i

​  

L+m  

i

​  

c  

w

​  

δt  

where Δt= change in temperature of water and copper vessel

m  

w

​  

 = mass of water = 150g

m  

c

​  

 = mass of copper vessel = 100g

m  

i

​  

 = mass of ice

c  

c

​  

 = specific heat capacity of copper

c  

w

​  

 = specific heat capacity of water

L = specific latent heat of fusion of ice

δt = change in temperature of ice

Therefore, [150×4.2×(50−5)]+[100×0.4×(50−5)]=(m×336)+[m×4.2×(5−0)]

(150×4.2×45)+(100×0.4×45)=(m×336)+(m×4.2×m)

28350+1800=336m+21m

357m=30150

m=  

357

30150

​  

=84.45g of ice

Hence, 84.45g of ice is needed to cool it to 5°C

Answer 2

Answer:

hope it's help full for u