A copper wire bent of a square encloses an area of 272.25 if the same wire is bent into the form of circle what will be the area enclosed by wire.
Answers
Answered by
1
Area of the square =272.25cm
2
Let a be the side of the square.
Thus, a
2
=272.25
=>a=
272.25
=>a=16.5 cm
Length of the wire is same, thus
Perimeter of the square= circumference of the circle
=>4a=2πr
=>r=
22
2a×7
=>r=
22
2×16.5×7
=>r=10.5cm
Now area of the circle =πr 2
=
7
22
(10.5) 2
=346.5cm 2
Answered by
1
Area of the square =272.25cm
2
Let a be the side of the square.
Thus, a
2
=272.25
=>a=
272.25
=>a=16.5 cm
Length of the wire is same, thus
Perimeter of the square= circumference of the circle
=>4a=2πr
=>r=
22
2a×7
=>r=
22
2×16.5×7
=>r=10.5cm
Now area of the circle =πr 2
=
7
22
(10.5) 2
=346.5cm 2
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