Question

A copper wire has a diameter 0.5 mm and resistivity of 1.6 into 10 to the power minus 8 ohm metre what will be the length of this wire to make its resistance 10 ohm how much does the resistance change if the diameter is double ok​

Answer 1

Answer:

R = pho L / A

• Length constant
• R ~ 1/A ~ 1/d^2

Volume constant

v= A × L

L = v/a

R = pho V/A^2

R ~ 1/d^4