A copper wire has a diameter 0.5 mm and resistivity of 1.6 into 10 to the power minus 8 ohm metre what will be the length of this wire to make its resistance 10 ohm how much does the resistance change if the diameter is double ok
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Answer:
R = pho L / A
- Length constant
- R ~ 1/A ~ 1/d^2
Volume constant
v= A × L
L = v/a
R = pho V/A^2
R ~ 1/d^4
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