A copper wire has a diameter of 0.5 mm and a resistivity of 1.68 x 10-8 ohm m What will be the length of this wire be to make its resistance 2 ohm? Class 10 physics Best answer will be marked BRAINLIEST or spamming will be reported asap
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Answer:
Length of the wire = 24.54 m
Explanation:
Given,
Diameter = 0.5 mm = 0.0005 m
Resistivity ρ = 1.68 * 10⁻⁸ Ωm
Resistance R = 2 Ω
Area of cross section A = π(d/2)²
Let us assume length of the wire as l.
We know that,
R = (ρl)/A
Then,
l = (RA/ρ)
= {2 * 3.14 * (0.0005/2)²}/{1.68 * 10⁻⁸}
= (2 * 3.14 * 25)/(4 * 1.6)
= 24.54 m
Therefore,
Length of the wire = 24.54 m
Note : In the above answer, he has taken resistance as 10 ohm but in the given question it is 2 ohm.
Hope it helps!
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