A copper wire has a diameter of 0.5mm and resistivity of 1.6×10-5 Ωm. what will be the length
of this wire to make its resistance 10 Ω?
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★Given :-
- Resistivity ρ = 1.6 × 10⁻⁸ Ω m
- Resistance R = 10 Ω
- Diameter d = 0.5 mm
★To find:-
- Length of the wire.
★Solution:-
Given diameter = 0.5mm
Therefore,
Radius = Diameter/2
=0.25mm
Converting units,
Radius r = 0.25 mm
= 0.25 × 10⁻³ m
= 2.5 × 10⁻⁴ m
Area = 6.25 π × 10⁻⁸ m²
Using the formula :-
✦R = ρ ( L ) / ( A )
Putting values :
➟ L = ( R × A ) / ρ
➟ L = ( 10 × 6.25 π × 10⁻⁸ ) / 1.6 × 10⁻⁸ m
➟ L = 62.5 π / 1.6
➟ L = 122.72 m
Hence,the length of wire is 122.72m.
_________________
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