A copper wire is 1.0 m in diameter and has a resistance of 10
Answers
Answered by
0
what do you want to ask please refresh your question
Answered by
0
Best Answer
Here
R = 10 ohm
l = 0.1 m
A = 3.14 * r ^ 2 = 3.14 * (d / 2) ^ 2
A = 3.14 * (0.2/2) ^ 2 sq. mm
A = 3.14 * 0.1 * 0.1 * 10 ^ (-6) sq. m
A = 3.14 * 10 ^(-8) sq. m
We know that
R = p * l / A where p = resistivity
therefore
p = R * A / l
p = 10 * 3.14 * 10^(-8) / 0.1
On calculating, we get
p = 3.14 * 10 ^(-6) ohm metre .
Thanks !!!
Hope u understand it!!
Here
R = 10 ohm
l = 0.1 m
A = 3.14 * r ^ 2 = 3.14 * (d / 2) ^ 2
A = 3.14 * (0.2/2) ^ 2 sq. mm
A = 3.14 * 0.1 * 0.1 * 10 ^ (-6) sq. m
A = 3.14 * 10 ^(-8) sq. m
We know that
R = p * l / A where p = resistivity
therefore
p = R * A / l
p = 10 * 3.14 * 10^(-8) / 0.1
On calculating, we get
p = 3.14 * 10 ^(-6) ohm metre .
Thanks !!!
Hope u understand it!!
Similar questions