Question

A copper wire is 1.0 m in diameter and has a resistance of 10

Answer 1

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Answer 2

Best Answer

Here 
R = 10 ohm 
l = 0.1 m 
A = 3.14 * r ^ 2 = 3.14 * (d / 2) ^ 2 
A = 3.14 * (0.2/2) ^ 2 sq. mm 
A = 3.14 * 0.1 * 0.1 * 10 ^ (-6) sq. m 
A = 3.14 * 10 ^(-8) sq. m 

We know that 
R = p * l / A where p = resistivity 
therefore 
p = R * A / l 
p = 10 * 3.14 * 10^(-8) / 0.1 

On calculating, we get 
p = 3.14 * 10 ^(-6) ohm metre . 

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