A copper wire is bending in the form of a square having an area of 484 cm square. if the same wire is bend in the form of a circle, what is the area of circle? ? .
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area of square = side× side
484 = side× side
therefore side = √484
side = 22 cm
perimeter of square = 4× side
= 4×22
=88 cm
perimeter of square = perimeter of circle
88 cm = 2πr
∴ r = 88÷ 2π
r = 14 cm
area of circle = πr²
∴ area of circle = π×14×14
= 576 cm²
484 = side× side
therefore side = √484
side = 22 cm
perimeter of square = 4× side
= 4×22
=88 cm
perimeter of square = perimeter of circle
88 cm = 2πr
∴ r = 88÷ 2π
r = 14 cm
area of circle = πr²
∴ area of circle = π×14×14
= 576 cm²
Answered by
0
given,
area of square = 484 sq.cm
s × s = 484
s =√484 = 22 cm
then, the perimeter of square = 4 × s
= 4× 22 = 88 cm
perimeter of square = perimeter of circle
88 = 2πr
88 = 2 × 22/7 × r
88× 7/ 44 = r
14 cm = r
required area of circle = πr²
= 22/7 × ( 14)²
= 22/7 × 196
= 22× 28
= 616 cm²
area of square = 484 sq.cm
s × s = 484
s =√484 = 22 cm
then, the perimeter of square = 4 × s
= 4× 22 = 88 cm
perimeter of square = perimeter of circle
88 = 2πr
88 = 2 × 22/7 × r
88× 7/ 44 = r
14 cm = r
required area of circle = πr²
= 22/7 × ( 14)²
= 22/7 × 196
= 22× 28
= 616 cm²
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