A copper wire length 2 meter and cross section area 1.7*10-6meter resistivity of 2*10-2ohm
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Answer:
1.7×10⁻8
Explanation:
R=Ρl÷A
so p=RA/l
=2×10-2×1.7×10-6/2
=1.7×10-8 ohm m
venky14800:
was it help full
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