A copper wire of conductance 0.2 mho has length 50 cm and
radius 0.1 mm. Calculate its resistivity and conductivity.
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Given:- A copper wire of conductance 0.2 ohm has length 50 cm and radius 0.1 mm.
To find:- Its resistivity and conductivity
Solution:- According to the question, the length of the wire is 50cm = 0.5 meter
and radius of the wire is 0.1 mm = 0.1/1000 meter =1×10^(-4)
So, R= 0.2 A= πr²= 3.14×10^(-8) (r=radius) L = 50 cm = 0.5 meter
we know,
Resistivity = R×A/L ohm.m
= 0.2×3.14×10^(-8) / 0.5 = 1.25 × 10^(-8) ohm.m
and we know,
Conductivity = L/(R×A) ohm.m
= 0.5/ [ 0.2×3.14×10^(-8)] ohm.m
= 79.6×10^6 ohm.m
So, its resistivity and conductivity are respectively 1.25 × 10^(-8) ohm.m and 79.6×10^6 ohm.m
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