Question

A copper wire of length 25 cm is in a magnetic field of 0.20 T. If it has a mass of 10 g, what is the minimum current through the wire that would cause a magnetic force equal to its weight?

Answer 1

Answer:

F(weight) = F(magnetic)

F(weight) = mg and F(magnetic) = BIL

m=0.01kg

g=9.8N

B=0.2T

I=?

L=0.25m

Therefore:

0.01 x 9.8 = 0.2 x I x 0.25

0.098 = 0.05I

I=0.098 / 0.05

I=1.96A

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Answer 2

The answer is 2.0A

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