A copper wire of length 25 cm is in a magnetic field of 0.20 T. If it has a mass of 10 g, what is the minimum current through the wire that would cause a magnetic force equal to its weight?
Answers
Answered by
8
Answer:
F(weight) = F(magnetic)
F(weight) = mg and F(magnetic) = BIL
m=0.01kg
g=9.8N
B=0.2T
I=?
L=0.25m
Therefore:
0.01 x 9.8 = 0.2 x I x 0.25
0.098 = 0.05I
I=0.098 / 0.05
I=1.96A
Pls mark me as brainliest
Answered by
1
The answer is 2.0A
#SPJ3
Attachments:
Similar questions