A copper wire when been in a form of a square encloses an area of 121 CM square if the same wire is bent into the form of a circle find the area of the circle
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Given,
Area of square= 121 cm²
Side of square= 11 cm
Perimeter of square= 44 cm
So,
Circumference of circle= 44 cm
2πr= 44
22/7*r= 22
r= 7 cm
Area of circle= πr²
= (22/7)*7*7
= 22*7
= 154 cm²
Hope this helps you!
Area of square= 121 cm²
Side of square= 11 cm
Perimeter of square= 44 cm
So,
Circumference of circle= 44 cm
2πr= 44
22/7*r= 22
r= 7 cm
Area of circle= πr²
= (22/7)*7*7
= 22*7
= 154 cm²
Hope this helps you!
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Answered by
1
Area enclosed in a square = 121 cm.
Area of a square = side × side
121 = s^2
S = √121 = 11cm.
Perimeter of square = 4 × S = 4 × 11 = 44 cm.
Now, Peri. of square = Peri. of circle
44 = 2 × 22/7 × radius
44 × 7/22 = 2 × r
r = 7cm.
Therefore area of the Circle = π × r × r
= 22/7 × 7 ×7
154 cm^2
Area of a square = side × side
121 = s^2
S = √121 = 11cm.
Perimeter of square = 4 × S = 4 × 11 = 44 cm.
Now, Peri. of square = Peri. of circle
44 = 2 × 22/7 × radius
44 × 7/22 = 2 × r
r = 7cm.
Therefore area of the Circle = π × r × r
= 22/7 × 7 ×7
154 cm^2
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