A cord is used to lower vertically a block of mass M, through a distance d at a constant downward acceleration of g/4
. Then the work done by the cord on the block is
Answers
Answered by
0
Explanation:
Mg−T=Ma=M(
8
g
)
⇒T=M(g−
8
g
)=
8
7
Mg
Work done by the cord : W=T×dcos180
∘
=
8
7
Mgd(−1)=−7Mgd/8
Answered by
1
Answer:
The work done by the cord on the block is - 3 Mg d/4.
Explanation:
Given: Mass = M
displacement = d
downward acceleration g/4.
To find: Work done by the cord.
Solution: Through the concept of #Pseudo Force, we know that:
Tension, T = m (g-a)
For the above case:
T = M ( g - g /4)
T = 3 Mg/4
#For work done, we know that:
W = F s cos∅
W = 3 Mg/4 × d × cos 180°
[∵ T = F = 3 Mg/4 and ∅ = 180° for the cord is descending straightly]
W = - 3 Mg d/4
Hence, the work done by the cord on the block is - 3 Mg d/4.
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