Question

A cornflakes box measures 30cm by 24cm by 8 cm calculate the surface area of the box​

Answer 1

Given,

The dimensions of the box are 30cm,24cm and 8cm.

Length = 30cm

Breadth = 24cm

Height = 8cm

Note: From the given data we can say that the box is in cuboid shape as it has 3 dimensions.

To find out,

The surface area of the box (cuboid).

Solution:

$surface \: area \: of \: cuboid \: (tsa) =2(lb + bh + hl) \\ \\ = 2(30 \times 24 + 24 \times 8 + 8 \times 30) \\ \\ = 2(720 + 192 + 240) \\ \\ = 2(1152) \\ \\ = 2304 \: {cm}^{2}$

Therefore the surface area of the box is 2304cm^2.

Answer 2

$\huge\mathbb{SOLUTION:-}$

$\bf{Given:-}\begin{cases}\sf{Dimensions\:of\:box}\\ \sf{length (l)=30cm}\\ \sf{breadth(b)=24cm}\\ \sf{height (h)=8cm}\end{cases}$

$\huge\star{\sf{\red{To\:Find:-}}}$

●The surface area of box

$\bf\underline{\underline{According\:To\: Question:-}}$

• The box is in the form of cuboid now we have to find the surface area of cuboid

$\boxed{\sf{\star{Surface\:Area\:of\:cuboid=2(lb+bh+hl}}}$

$\sf\implies Surface Area=2(30\times 24+24\times 8+8\times 30\\ \\ \sf\implies Surface\:area=2(720+192+240\\ \\ \sf\implies Surface\:Area=2\times 1152\\ \\ \sf\implies Surface\:Area= 2304cm{}^{2}$

• The surface area of cuboid is 2304

$\boxed{\huge{\star}{\sf{\red{Surface\:area\:of\:box=2304cm{}^{2}}}}}$