a cottage industry produces a certain number of pottery articles in a day it was observed on a particular days at the cost of production of each article was 3 more than twice the number of articles produced on that day if the total cost of production on that there was rupees 90 find the number of articles produced and the cost of each article
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Given :-
The total cost of production= Rs.90
Let the number of pottery articles produced be x
Therefore , cost of production of each article = Rs (2x + 3)
the total cost of production = no. of pottery articles produced × cost of production
According To The Question ,
90 = x(2x + 3) = 0
⇒ 2x²+ 3x – 90 = 0
⇒ 2x² + 15x -12x – 90 = 0
⇒ x(2x + 15) -6(2x + 15) = 0
⇒ (2x + 15)(x – 6) = 0
Now 2x + 15 = 0
⇒2x = - 15
⇒x = -15/2
⇒x – 6 = 0
⇒x = 6
⇒ x = -15/2 or x = 6
As the number of articles produced can only be a positive integer, therefore, x can only be 6
Hence , number of articles produced = 6
Cost of each article = 2 × 6 + 3 = Rs 15
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