A cottage industry produces a certain number of pottery article in a day . It was observed on a particular day that the cost of production of each article in rupes was 3 more than twice 5he no. Of
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Step-by-step explanation:
Given: The total cost of production= Rs.90
Let the number of pottery articles produced be x.
Therefore, cost of production of each article = Rs (2x + 3)
the total cost of production = no. of pottery articles produced × cost of production
A.T.Q
90.= x(2x + 3) = 0
⇒ 2x²+ 3x – 90 = 0
⇒ 2x² + 15x -12x – 90 = 0
⇒ x(2x + 15) -6(2x + 15) = 0
⇒ (2x + 15)(x – 6) = 0
Now 2x+15=0 ⇒2x= - 15
⇒x= -15/2
⇒x – 6 = 0
⇒x=6
⇒ x = -15/2 or x = 6
As the number of articles produced can only be a positive integer, therefore, x can only be 6.
Hence, number of articles produced = 6
Cost of each article = 2 × 6 + 3 = Rs 15.
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