Question

A cottage industry produces a certain number of pottery articles in a day. It was observed on a particular day that the cost of production of each article (in rupees) was 3 more than twice the number of articles produced on that day. If the total cost of production on that day was Rs 90, find the number of articles produced and the cost of each article.

Answer 1

Let us assume, number of pottery in a day = x

So, cost of production of each article = 2x + 3

As per question; x(2x + 3) = 90

Or, 2x2 + 3x = 90

Or, 2x2 + 3x – 90 = 0

Or, 2x2 – 12x + 15x – 90 = 0

Or, 2x(x – 6) + 15(x – 6) = 0

Or, (2x + 15)(x – 6) = 0

Hence, x = - 15/2 and x = 6

Ruling out the negative value; x = 6

Cost of article = Rs. 15

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Answer 2

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