Question

a cottage industry produces a certain number of pottery articles in a day it was observed on a particular day that the cost of production of each article was three more than the twice the number of article produced on that day if the total cost of production on that day was rupees 90 find the number of articles produced and the cost of each article

Answer 1

Hii There!!

Let the number of articles produced to be 'x'.

So, According to the question:-

Since, given total cost is Rs 90.

Therefore,
cost of production of each article =2x+3 Rs.

Now, total cost of production = no. of  pottery articles produced × cost of production

=) 90.= x(2x + 3) = 0

=) 2x²+ 3x – 90 = 0

=) 2x² + 15x -12x – 90 = 0

=) x(2x + 15) -6(2x + 15) = 0

=) (2x + 15)(x – 6) = 0

=) 2x+15=0 

=) 2x= - 15

=)x= -15/2

 =)x – 6 = 0

=)x=6

=) x = -15/2 or x = 6

Since, the number of articles produced can't be (-ve) .

So, No. of articles produced =6
Cost of each article will be = 2× 6+3 = 15Rs.


Hope it helps

#DK

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Answer 2

The totɑl cost of production= Rs.90

Let the number of pottery ɑrticles produced be x.
Therefore, cost of production of eɑch ɑrticle = Rs (2x + 3)      

the totɑl cost of production = no. of  pottery ɑrticles produced × cost of production

ɑ.T.Q

90.= x(2x + 3) = 0

⇒ 2x²+ 3x – 90 = 0
⇒ 2x² + 15x -12x – 90 = 0
⇒ x(2x + 15) -6(2x + 15) = 0
⇒ (2x + 15)(x – 6) = 0

Now 2x+15=0 ⇒2x= - 15

⇒x= -15/2


 ⇒x – 6 = 0

⇒x=6

⇒ x = -15/2 or x = 6

ɑs the number of ɑrticles produced cɑn only be ɑ positive integer, therefore, x cɑn only be 6.


Hence, number of ɑrticles produced = 6
Cost of eɑch ɑrticle = 2 × 6 + 3 = Rs 15.

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