A couple has 2 children. find the probability that both are boys, if it is known that (i) one of them is a boy (ii) the older child is a boy.
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4
(i) it may be 2/4
1/2
1/2
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0
Answer:
hey the answer is below :)
Step-by-step explanation:
Given that, a couple has 2 children,
Let B be a boy and G be a girl
Then the sample space, S = (BB, BG, GB, GG}
(i) The probability that one of them is a boy:
Let, A = atleast one of them is a boy {BB, BG, GB}
B = both are boys {BB}
Therefore, P(B/A) = P(A∩B)/ P(A)
= (¼)/(¾)
= ⅓
Therefore, the probability that one of them is a boy = ⅓
(ii) The probability that an older child is a boy:
Let, A = elder one is a boy {BB, BG}
B = both are boys {BB}
Therefore, P(B/A) = P(A∩B)/ P(A)
= (¼)/(2/4)
= ½
Therefore, the probability that elder one is a boy = 1/2
PLS MRK AS BRAINLIEST PLSSSSSSSSSSSSSSSSSS AS I HELPED U :)
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