A courtyard 20 m long &15 m broad is to be paved with bricks of length 25 cm & breadth 12 cm.Find no.Of brick required sol.?
Answers
Answered by
6
hey
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req no of bricks = area of courtyard/ area of bricks
= 20×15m^2 / 0.25×0.12m^2
= 300/0.03
= 300× 100 / 3
= 30000/3
= 10000 bricks
hope helped
______________
_______
req no of bricks = area of courtyard/ area of bricks
= 20×15m^2 / 0.25×0.12m^2
= 300/0.03
= 300× 100 / 3
= 30000/3
= 10000 bricks
hope helped
______________
Answered by
18
Here is your solution
Given :-
A courtyard 20 m long &15 m broad.
To find number of Bricks.
Required no of bricks = area of courtyard/ area of bricks.
=> 20×15m^2 / 0.25×0.12m^2
=> 300/0.03
=> 300× 100 / 3
=> 30000/3
=> 10000
hence,
Number of bricks is 10000 .
Hope it helps you
Given :-
A courtyard 20 m long &15 m broad.
To find number of Bricks.
Required no of bricks = area of courtyard/ area of bricks.
=> 20×15m^2 / 0.25×0.12m^2
=> 300/0.03
=> 300× 100 / 3
=> 30000/3
=> 10000
hence,
Number of bricks is 10000 .
Hope it helps you
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