Question

A courtyard 4.55 m long and 5.25 m broad is paved with square tiles of equal size. What is the largest size of tile used?

Answer 1

Answer:

The largest size of the tile used is 35 cm

Step-by-step explanation:

Length of the courtyard = 4.55 m = 455 cm

breadth of the courtyard = 5.25 m = 525 cm

In order to find the largest size of the tiles, we need to find the HCF of 455 and 525

Now,

455 = 13 × 7 × 5

525 = 5² × 7 × 3

HCF of 455 and 525 = 5 × 7 = 35

Therefore, the largest size of the tile used = 35 cm

Hope this is helpful.

Answer 2

The largest size of the tile is 35 cm × 35 cm

Step-by-step explanation:

Given,

Length of the courtyard (l) = 4.55 m

Converting the m into cm by multiplying by 100

= 4.55 × 100

= 455 cm

Breadth of the courtyard (b) = 5.25 m

Converting the m into cm by multiplying by 100

= 5.25 × 100

= 525 cm

In order to find the largest size of tile, we have to compute the GCD or HCF of length as well as breadth GCD/HCF

So, HCF will be:

Length = 455 = 5 × 7 × 13

Breadth = 525 = 5 × 7 × 5 × 3

GCD or HCF = 5 × 7

= 35 cm

Therefore, the square tiles of sides 35 cm × 35 cm are the largest tiles.