A cow is tied with a rope of 12 m at corner of rectangular field dimensions 25 and 45 if the length of the rope is increased to 23 then the additional grassy area is
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- Step-by-step explanation:
- Given
- Given a rectangle of dimension length 45 m and width = 25 m. A rope of length 12 m is tied to cow.
- Area of rectangular field = length x breadth
- = 25 x 45
- = 1125 sq m
- In the quadrant, if the length is 12 m area to be grazed is π / 4 r^2
- = π / 4 x 12 x 12
- = 36 π m^2
- After extending Area to be grazed when length of rope is 23 m
- = π / 4 r^2
- = π / 4 x (23)^2
- Now area of additional grass area = π / 4 (23)^2 – 36 π
- = (23)^2 π – 36 x 4 π / 4
- = π ( (23)^2 – (12)^2 ) / 4
- = π (23 + 12) (23 – 12) / 4
- = π x 35 x 11 / 4
- = 302.5 sq m
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